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A particle of specific charge qm=π Ckg−1 is projected from the origin toward positive x−axis with a velocity of 10 ms−1 in a uniform magnetic field →B=−2^kT. The velocity →v of particle after time t=112 s will be (in ms−1)

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Solution

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Since the particle will be at point P after time t=112=T12s , it is deviated by an angle θ=2π12=300

Hence, velocity at point P

→v=10(cos300^i+sin300^j)=10(√32^i+12^j)=5(√3^i+1^j)=5(√3^i+^j)

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