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- 5[√3^i−^j]
- 5[^i+√3^j]
- 5[√3^i+^j]
- 5[^i+^j]

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Solution

Verified by Toppr

Since the particle will be at point P after time t=112=T12s , it is deviated by an angle θ=2π12=300

Hence, velocity at point P

→v=10(cos300^i+sin300^j)=10(√32^i+12^j)=5(√3^i+1^j)=5(√3^i+^j)

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