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Question

A particle of specific charge qm=π Ckg1 is projected from the origin toward positive xaxis with a velocity of 10 ms1 in a uniform magnetic field B=2^kT. The velocity v of particle after time t=112 s will be (in ms1)
  1. 5[3^i^j]
  2. 5[^i+3^j]
  3. 5[3^i+^j]
  4. 5[^i+^j]

A
5[3^i+^j]
B
5[3^i^j]
C
5[^i+3^j]
D
5[^i+^j]
Solution
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Time period T=2πmqB=2πqmB=2ππ×2=1s

Since the particle will be at point P after time t=112=T12s , it is deviated by an angle θ=2π12=300

Hence, velocity at point P

v=10(cos300^i+sin300^j)=10(32^i+12^j)=5(3^i+1^j)=5(3^i+^j)

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