Question

# A particle of specific charge qm=π Ckg−1 is projected from the origin toward positive x−axis with a velocity of 10 ms−1 in a uniform magnetic field →B=−2^kT. The velocity →v of particle after time t=112 s will be (in ms−1)

A
5[^i+3^j]
B
5[3^i+^j]
C
5[3^i^j]
D
5[^i+^j]
Solution
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#### Time period T=2πmqB=2πqmB=2ππ×2=1sSince the particle will be at point P after time t=112=T12s , it is deviated by an angle θ=2π12=300Hence, velocity at point P→v=10(cos300^i+sin300^j)=10(√32^i+12^j)=5(√3^i+1^j)=5(√3^i+^j) 0
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