Question

# A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by

A
2β2x2n+1
B
2nβ2e4n+1
C
2nβ2x2n1
D
2nβ2x4n1
Solution
Verified by Toppr

#### v(x)=βx−2n

18
Similar Questions
Q1

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx2n ,where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :

View Solution
Q2

If (1+i1i)x=1, then

View Solution
Q3

The position x of a particle varies with time t as x=aeαt+beβt, where a,b,α and β are positive constants. The velocity of the particle will

View Solution
Q4

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
v(x)=βx2n
where β and n are constants and x is the position of the particle. The acceleration of the particle, as a function of x, is given by

View Solution
Q5

A particle of unit mass undesgro one dimension motion. Such that its verocity varies accordingly to v(x) = βx2π,where β and n are constant and x is the position of the particle. The accelerationx is the position of the particle. The accelerationof the particle a function of x, is given by

View Solution
Solve
Guides