A particle performing SHM is found its equilibrium t-1sec- and it is found to have a speed of 0-25 m-s t-2 sec- If the period of oscillation is 6 sec - calculate amplitude of oscillation-displaystylefrac-3-2pi-mdisplaystylefrac-3-8pi-displaystylefrac-6-pi-mdisplaystylefrac-3-4pi-m

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Toppr Admin · Accepted Answer

Since a SHM can be represented by x-Asin-x3C9-t-x3D5-

A particle performing SHM is found at its equilibrium at t=1sec, and it is found to have a speed of 0.25 m/s at t=2 sec. If the period of oscillation is 6 sec , calculate amplitude of oscillation.
$\frac{3}{2 π} m$
$\frac{3}{8 π}$
$\frac{6}{π} m$
$\frac{3}{4 π} m$

Since a SHM can be represented by $x = A sin (ω t + ϕ)$

A particle performing SHM is found at its equilibrium at t=1sec, and it is found to have a speed of 0.25 m/s at t=2 sec. If the period of oscillation is 6 sec , calculate amplitude of oscillation.32πm38π6πm34πm

Since a SHM can be represented by x=Asin(ωt+ϕ)

A particle performing SHM is found at its equilibrium at t=1sec, and it is found to have a speed of 0.25 m/s at t=2 sec. If the period of oscillation is 6 sec , calculate amplitude of oscillation.
$\frac{3}{2 π} m$
$\frac{3}{8 π}$
$\frac{6}{π} m$
$\frac{3}{4 π} m$

Since a SHM can be represented by $x = A sin (ω t + ϕ)$