Question

# A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be: A
110m/s
B
55m/s
C
550m/s
D
660m/s
Solution
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#### Given,u=0m/s Particle initially at restAcceleration, a=dvdtdv=adtv=∫adt. . . . . . . . .(1)From the above equation, velocity of the particle is equal to the area under the acceleration-time curve.From the given acceleration-time graph,vmax=12×base×heightvmax=12×11×10vmax=55m/sThe correct option is B.

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