A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be:
660m/s
55m/s
110m/s
550m/s
A
55m/s
B
550m/s
C
660m/s
D
110m/s
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Solution
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Given,
u=0m/s Particle initially at rest
Acceleration, a=dvdt
dv=adt
v=∫adt. . . . . . . . .(1)
From the above equation, velocity of the particle is equal to the area under the acceleration-time curve.
From the given acceleration-time graph,
vmax=12×base×height
vmax=12×11×10
vmax=55m/s
The correct option is B.
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