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Question

- 660m/s
- 55m/s
- 110m/s
- 550m/s

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Solution

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Given,

u=0m/s Particle initially at rest

Acceleration, a=dvdtdv=adt

v=∫adt. . . . . . . . .(1)

From the above equation, velocity of the particle is equal to the area under the acceleration-time curve.

From the given acceleration-time graph,

vmax=12×base×height

vmax=12×11×10

vmax=55m/s

The correct option is B.

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