A particle starts performing simple harmonic motion. Its amplitude is A. At one time its speed is half that of the maximum speed. At this moment the displacement is:
√2A3
√3A2
3A√2
2A√2
A
√3A2
B
2A√2
C
3A√2
D
√2A3
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Solution
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v=ω√A2−x2 ∴ωA2=ω√A2−x2 or x=√32A
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