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Correct option is B)

$s_{1}=V_{0}x(2t )(AtoB)$

$t_{2}=(23−S )/V_{1}$

$t_{2}=(2S−V_{0}(t/2) )/V_{1}$

$t+2=2V_{1}S −V_{1}V_{0} ×4t $

$(2t −t_{2})=V_{2}(2S−S_{1} ) $

$2t −(2V_{1}3 −4V_{1}V_{0}t )=2V_{2}S−S_{1} $

$2t −2V_{1}S +4V_{1}V_{0}t =2V_{2}3−V_{0}t/2 $

$2t −2V_{1}3 +4V_{1}V_{0}t =2V_{2}S −4V_{2}V_{0} t$

$t(21 +4V_{1}V_{0} +4V_{2}V_{0} )=S(2V_{2}1 +2V_{1}1 )$

$V_{arg}=tS =4V_{1}V_{2}2V_{1}V_{2}+V_{0}(V_{1}+V_{2}) /2V_{1}V_{2}14+V_{2} $

$tS =2V_{1}V_{2}(V_{1}+V_{2}) 2V_{1}V_{2}2V_{1}V_{2}+V_{0}(V_{1}+V_{2}) $

$V_{avg}=2(V_{1}+V_{2})V_{0}(V_{1}+V_{2})+2V_{1}V_{2} $

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