A particular 12V car battery can send a total charge of 84 A-h -ampere-hours- through a circuit- from one terminal to the other-a- How many coulombs of charge does this represent-b- If this entire charge undergoes a change in electric potential of 12V- how much energy is involved-

Question

A particular 12V car battery can send a total charge of 84  A-h -ampere-hours- through a circuit- from one terminal to the other-a- How many coulombs of charge does this represent-b- If this entire charge undergoes a change in electric potential of 12V- how much energy is involved-

Toppr Admin · Accepted Answer

-a- An ampere is a coulomb per second- so-160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- - 84 - A-h - -bigg- 84 -dfrac-C-h-s- -bigg- -bigg- 3600 -dfrac-s-h- -bigg- -3-0 -times 10-5 - C-b- The change in potential energy is - -Delta U - q -Delta V - -3-0 -times 10-5 - C-12 - V-3-6 -times 10-6 - J- -160-160-

A particular $$12V$$ car battery can send a total charge of $$84 \ A.h$$ (ampere-hours) through a circuit, from one terminal to the other.
(a) How many coulombs of charge does this represent?
(b) If this entire charge undergoes a change in electric potential of $$12V$$, how much energy is involved?

(a) An ampere is a coulomb per second, so
$$ 84 \ A.h = \bigg( 84 \dfrac{C.h}{s} \bigg) \bigg( 3600 \dfrac{s}{h} \bigg) =3.0 \times 10^5 \ C.$$
(b) The change in potential energy is $$ \Delta U = q \Delta V = (3.0 \times 10^5 \ C)(12 \ V)=3.6 \times 10^6 \ J. $$

A particular $$12V$$ car battery can send a total charge of $$84 \ A.h$$ (ampere-hours) through a circuit, from one terminal to the other.(a) How many coulombs of charge does this represent?(b) If this entire charge undergoes a change in electric potential of $$12V$$, how much energy is involved?

(a) An ampere is a coulomb per second, so $$ 84 \ A.h = \bigg( 84 \dfrac{C.h}{s} \bigg) \bigg( 3600 \dfrac{s}{h} \bigg) =3.0 \times 10^5 \ C.$$(b) The change in potential energy is $$ \Delta U = q \Delta V = (3.0 \times 10^5 \ C)(12 \ V)=3.6 \times 10^6 \ J. $$

A particular $$12V$$ car battery can send a total charge of $$84 \ A.h$$ (ampere-hours) through a circuit, from one terminal to the other.
(a) How many coulombs of charge does this represent?
(b) If this entire charge undergoes a change in electric potential of $$12V$$, how much energy is involved?

(a) An ampere is a coulomb per second, so
$$ 84 \ A.h = \bigg( 84 \dfrac{C.h}{s} \bigg) \bigg( 3600 \dfrac{s}{h} \bigg) =3.0 \times 10^5 \ C.$$
(b) The change in potential energy is $$ \Delta U = q \Delta V = (3.0 \times 10^5 \ C)(12 \ V)=3.6 \times 10^6 \ J. $$