A path of width 8 m runs around a circular park whose radius is $38 m$ . Find the area of the path.

$2112 m^{2}$
$2834 m^{2}$
$1578 m^{2}$
$3212 m^{2}$

Question

A path of width 8 m runs around a circular park whose radius is 38 m- Find the area of the path-2112 m-22834 m-21578 m-23212 m-2

Toppr Admin · Accepted Answer

Inner radius -Radius of the park- -38-xA0-mOuter radius -Radius of the park - path width of the park-xA0-38-8-46-xA0-mArea of the path -x3C0-462-x2212-382-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-227-2116-x2212-1444-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-227-672-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-2112-xA0-m2

A path of width 8 m runs around a circular park whose radius is 38 m. Find the area of the path.2112 m22834 m21578 m23212 m2

Inner radius (Radius of the park) =38 mOuter radius (Radius of the park + path width of the park) =38+8=46 mArea of the path =π(462−382) =227(2116−1444) =227(672) =2112 m2

A path of width 8 m runs around a circular park whose radius is $38 m$ . Find the area of the path.

$2112 m^{2}$
$2834 m^{2}$
$1578 m^{2}$
$3212 m^{2}$

Inner radius (Radius of the park) $= 38 m$
Outer radius (Radius of the park $+$ path width of the park) $= 38 + 8 = 46 m$
Area of the path $= π (46^{2} - 38^{2})$
$= \frac{22}{7} (2116 - 1444)$
$= \frac{22}{7} (672)$
$= 2112 m^{2}$