Question

A pendulum clock is sec fast at temperature of and sec slow at a temperature of . At temperature does it give the correct time-

A

B

C

D

Medium

Solution

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Correct option is B)

and , linear expansion formula
change in temperatureFinalinitial
sec fast hour alarm rises sec before i.e., time period reduced
Case I:
sec fast at C
……..
temperature at which correct reading.
Case II:
sec slow at C
sec
………
Heated to C
dividing by
We get
.

Solve any question of Thermal Properties Of Matter with:-

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