Question

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Solution

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Correct option is C)

Maximum velocity is given by $v_{max}=Aw$

where $A$ is the amplitude of oscillation and $w$ is the angular frequency given by $w=lg $

$∴$ For the same length of the string, $w$ remains the same.

$⟹v_{max}∝A$

Thus $A_{′}=2A⟹v_{max}=2v$

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