A person carries a hammer on his shoulder and holds the other end of its light handle in his hand. Let y be the distance between his hand and the point of support. If the person changes y, the pressure on his hand will be proportional to:
Open in App
Verified by Toppr
Correct option is C)
As it is clear from the Free body diagram, for the hammer to be in equilibrium condition following should be followed : F×y=w×(l−y) which gives; F×y=w×l−w×y y=F+ww×l w×lF+w=y1 Let w×l=d and l1=c Hence the new equation becomes; dF+c=y1 which gives F=yd−c×d Let c×d=a , which gives F+a=yd As "a" being a constant does not effect proportionality we have F inversely proportional to y.