A person wants to see two pillars from a distance of 11 km, separately. The distance between the pillars must be approximately
3.2m
1m
0.25 m
0.5 m

Question

A person wants to see two pillars from a distance of 11 km- separately- The distance between the pillars must be approximately3-2m1m0-25 m0-5 m

Toppr Admin · Accepted Answer

Resolving power of eye - 1-x2032-x3C0-60-xD7-180radians -approximately-Let the separation between pillars -xmDistance -11000m-gt- x11000-x3C0-60-xD7-180-gt- x-3-2m -approximately-Answer- A-3-2m

A person wants to see two pillars from a distance of 11 km, separately. The distance between the pillars must be approximately3.2m1m0.25 m0.5 m

Resolving power of eye = 1′=π60×180radians (approximately)Let the separation between pillars =xmDistance =11000m=> x11000=π60×180=> x=3.2m (approximately)Answer. A)3.2m

A person wants to see two pillars from a distance of 11 km, separately. The distance between the pillars must be approximately
3.2m
1m
0.25 m
0.5 m

Resolving power of eye = $1^{'} = \frac{π}{60 \times 180} r a d i a n s$ (approximately)

Let the separation between pillars $= x m$
Distance $= 11000 m$

=> $\frac{x}{11000} = \frac{π}{60 \times 180}$

=> $x = 3.2 m$ (approximately)

Answer. A) $3.2 m$