A photometal is illuminated by lights of wavelengths λ1andλ2 respectively. The maximum kinetic enegies of electrons emitted in the two cases are E1 and E2 respectively. The work function of metal is
E2λ1−E1λ2λ1
E1λ1+E2λ2λ1−λ2
E2λ2−E1λ1λ1−λ2
E1λ1−E2λ2λ1+λ2
A
E1λ1+E2λ2λ1−λ2
B
E2λ1−E1λ2λ1
C
E2λ2−E1λ1λ1−λ2
D
E1λ1−E2λ2λ1+λ2
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Solution
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E1=hcλ1−ϕ−−−−−−−−−−(1)
⇒(E1+ϕ)λ1=hc−−−−−−−−−−(2) E2=hcλ2−ϕ−−−−−−−−−−−−−(3) Now, substituting value of hc from (2) to (3) E2=(E1+ϕ)λ1λ2−ϕ E2λ2=E1λ1+ϕλ1−ϕλ2 E2λ2−E1λ1λ1−λ2=ϕ
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