A piece of ice (heat capacity =2100Jkg−1oC−1 and latent heat =3.36×105Jkg−1) of mass m grams is at −5oC at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m is
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9
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Solution
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Heat = latent heat + Heat required to raise temp Q=mL+mCpΔT 420=(m×2100×5+1×3.36×105)×10−3 where m is in gm. m=8g
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