Area A=7m2, Normal ^n=1√50(3^i−5^j+4^k)
≃17(3^i−5^j+4^k)
∴ area →A=(3^i−5^j+4^k)m2
Magnetic field →B=(0.2^i+0.2^j−0.3^k)T
Current I=2A
∴ magnetic moment →M=I→A=(6^i−10^j+8^k)Am2
|→M|≃14Am2(2×7=14)
Potential energy U=−→M.→B
=−[1.2−2−2.4]=3.2J
Let θ be the angle between ^n and →B(i.e.,)between →M and →B.
Now,U=−MBcosθ.
∴cosθ=−UMB=−3.214×0.4(∵√0.17≃0.4)
=−47=−0.57
θ=π−cos−1(0.57)