A plane mirror is held at a height h above the bottom of an empty beaker. The beaker is now filled with water up to depth d. The general expression for the distance from a scratch at the bottom of the beaker to its image in terms of h and the depth d of water in the beaker is :
2h−d(μμ−1)
2h−d(μ−1μ)
2h−d(2μ−1μ)
2h−d2(μ−1μ)
A
2h−d2(μ−1μ)
B
2h−d(μ−1μ)
C
2h−d(μμ−1)
D
2h−d(2μ−1μ)
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Solution
Verified by Toppr
shift observed is d(1−1μ)
object distance wrt mirror is h−shift=h−d(1−1μ)
image distance from mirror is h−d(1−1μ)
distance of image from the scratch at the bottom of beaker is h−d(1−1μ)+h=2h−d(μ−1μ)
option C is correct
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