Solve Study Textbooks Guides

Use app

Login

Question

A plane mirror is held at a height h above the bottom of an empty beaker. The beaker is now filled with water up to depth $d$ . The general expression for the distance from a scratch at the bottom of the beaker to its image in terms of $h$ and the depth $d$ of water in the beaker is :

A

$2 h - d (\frac{μ}{μ - 1})$

B

$2 h - \frac{d}{2} (\frac{μ - 1}{μ})$

C

$2 h - d (\frac{μ - 1}{μ})$

D

$2 h - d (\frac{2 μ - 1}{μ})$

Hard

Open in App

Solution

Verified by Toppr

Correct option is C)

shift observed is $d (1 - \frac{1}{μ})$

object distance wrt mirror is $h - s h i f t = h - d (1 - \frac{1}{μ})$

image distance from mirror is $h - d (1 - \frac{1}{μ})$

distance of image from the scratch at the bottom of beaker is $h - d (1 - \frac{1}{μ}) + h = 2 h - d (\frac{μ - 1}{μ})$

option $C$ is correct

Was this answer helpful?

0

0

Similar questions

A man of height 170 cm wants to see his complete image in a plane mirror (while standing). His eyes are at a height of 160 cm from the ground.

A boy of height 1.5 m with his eye level at 1.4 m stands before a plane mirror of length 0.75 m fixed on the wall. The height of the lower edge of the mirror above the floor is 0.8 m. Then :

Consider the situation shown in Fig. Water $(μ = 4 / 3)$ is filled in a beaker upto a height of $10 c m$ .
A plane mirror is fixed at a height of $5 c m$ from the surface of water. Distance of image from the mirror after reflection from it of an object $O$ at the bottom of the beaker is

159217

A container is filled with water ( $μ =$ 1.33) upto a height of $33.25 c m$ . A concave mirror is placed $15 c m$ above the water level and the image of an object placed at the bottom is formed $25 c m$ below the water level. The focal length of the mirror is (nearly) :

6680

It is desired to photograph the image of an object placed at a distance of $3$ m from a plane mirror. The camera, which is at a distance of $4.5$ m from the mirror should be focused for a distance of :