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Question

A plane mirror is held at a height h above the bottom of an empty beaker. The beaker is now filled with water up to depth d. The general expression for the distance from a scratch at the bottom of the beaker to its image in terms of h and the depth d of water in the beaker is :
  1. 2hd(μμ1)
  2. 2hd(μ1μ)
  3. 2hd(2μ1μ)
  4. 2hd2(μ1μ)

A
2hd2(μ1μ)
B
2hd(μ1μ)
C
2hd(μμ1)
D
2hd(2μ1μ)
Solution
Verified by Toppr

shift observed is d(11μ)

object distance wrt mirror is hshift=hd(11μ)

image distance from mirror is hd(11μ)

distance of image from the scratch at the bottom of beaker is hd(11μ)+h=2hd(μ1μ)

option C is correct

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