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Correct option is A)

$v=−[22.5+22.5−x]=−(45−x)$

and object distance

$u=−x$

given focal length is

$f=−10$

So using mirror formula,

$v1 +u1 =f1 $

$−(45−x)1 +−x1 =−101 ⟹45x−x_{2}45 =101 $

$x_{2}−45x+450=0$

$(x−30)(x−15)=0$

Hence $x=30cm$ or $x=15cm$

.

But as the distance between the two mirror is $22.5$, $x=30$ is not admissible . So the object must be at a distance of $15$ cm from the concave mirror

But as the distance between the two mirror is $22.5$, $x=30$ is not admissible . So the object must be at a distance of $15$ cm from the concave mirror

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