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# A plane surface is inclined at an angle of 600 with the horizontal. A body of mass 10 kg is uniformly accelerating, along the inclined plane surface. The value of coefficient of friction μk, between the body and the inclined surface is 0.2, if the length of the inclined plane is 10 m, then the work done to pull it to the top is ( Take g=10 m/s2) 866 J966 J766 J666 J

A
766 J
B
666 J
C
966 J
D
866 J
Solution
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#### F =mg(sinθ+μkcosθ)=10×10×(√32+0.2×12)=100(0.966)=96.6NWork Done =F.s=96.6×10=966J

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