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# A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms−1, the escape velocity from the surface ofthe planet would be110kms−111kms−10.11kms−11.1kms−1

A
1.1kms1
B
11kms1
C
110kms1
D
0.11kms1
Solution
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#### Escape velocity=√2Gmrvnewvearth=√mnewrearthmearthrnew=  ⎷10110=10vnew=110 kms−1

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