A player tosses two fair coins- He wins Rs- 5- two heads occur- Rs- 2- one occurs and Rs- 1- no occurs- Then his expected gain isRs-dfrac-7-3-Rs-dfrac-8-3-Rs-2-5Rs-1-5

Question

Toppr Admin · Accepted Answer

Expected value-x2211-x-i-P-x-i-Expected gain-5-x2217-1-4-2-x2217-1-2-1-x2217-1-4-2-5

A player tosses two fair coins. He wins $R s . 5 / -$ if two heads occur, $R s .$ $2 / -$ if one head occurs and $R s .$ $1 / -$ if no head occurs. Then his expected gain is
$R s . \frac{7}{3}$
$R s . \frac{8}{3}$
$R s .2 .5$
$R s .1 .5$

Expected value $= \sum x (i) P (x (i))$
Expected gain $= 5 * 1 / 4 + 2 * 1 / 2 + 1 * 1 / 4 = 2.5$

A player tosses two fair coins. He wins Rs. 5/− if two heads occur, Rs. 2/− if one head occurs and Rs. 1/− if no head occurs. Then his expected gain isRs.73Rs.83Rs.2.5Rs.1.5

Expected value=∑x(i)P(x(i))Expected gain=5∗1/4+2∗1/2+1∗1/4=2.5

A player tosses two fair coins. He wins $R s . 5 / -$ if two heads occur, $R s .$ $2 / -$ if one head occurs and $R s .$ $1 / -$ if no head occurs. Then his expected gain is
$R s . \frac{7}{3}$
$R s . \frac{8}{3}$
$R s .2 .5$
$R s .1 .5$

Expected value $= \sum x (i) P (x (i))$
Expected gain $= 5 * 1 / 4 + 2 * 1 / 2 + 1 * 1 / 4 = 2.5$