Question

A point charge $+q$ is placed at mid point of a cube of side $L$. The electric flux emerging from the cube is

• A. $\frac{q}{{\epsilon }_0}$
• B. $\frac{6q{l}^2}{{\epsilon }_0}$
• C. $\frac{q}{6l^2{\epsilon }_0}$
• D. $zero$

Answer 1

Answer: (A)

Gauss law: $\oint E\cdot da=\frac{q_{enclosed}}{{\epsilon }_0}$
Now, the total flux emerging from the cube $=\frac{q}{{ϵ}_0}$ as $q$ is enclosed by cube.