A point charge -q-1- is moved along a circular path of radius r in the electric field of another point charge -q-2- the centre of the path- The work done by the electric field on the charge -q-1- in half revolution is

Question

Toppr Admin · Accepted Answer

Correct option is A- zeroWork done is zero- because force applied by -q-2- on -q-1- is always perpendicular to the velocity of -q-1-

A point charge $${q}_{1}$$ is moved along a circular path of radius $$r$$ in the electric field of another point charge $${q}_{2}$$ at the centre of the path. The work done by the electric field on the charge $${q}_{1}$$ in half revolution is

Correct option is A. zero
Work done is zero, because force applied by $${q}_{2}$$ on $${q}_{1}$$ is always perpendicular to the velocity of $${q}_{1}$$

A point charge $${q}_{1}$$ is moved along a circular path of radius $$r$$ in the electric field of another point charge $${q}_{2}$$ at the centre of the path. The work done by the electric field on the charge $${q}_{1}$$ in half revolution is

Correct option is A. zeroWork done is zero, because force applied by $${q}_{2}$$ on $${q}_{1}$$ is always perpendicular to the velocity of $${q}_{1}$$

Correct option is A. zero
Work done is zero, because force applied by $${q}_{2}$$ on $${q}_{1}$$ is always perpendicular to the velocity of $${q}_{1}$$