A point light is kept in front of a convex mirror ata distance of 40 cm- The focal length of the mirror is 40 cm- Find the position of image-

Question

Toppr Admin · Accepted Answer

Object distance-xA0-xA0- u-x2212-40-xA0-cmFocal length-xA0-xA0- f-40-xA0-cmUsing mirror-xA0- formula -xA0-xA0- 1v-1u-1fOr-xA0-xA0-xA0-  1v-1-x2212-40-1-40-We get-xA0-xA0- v-20-xA0-cm

A point light source is kept in front of a convex mirror ata distance of $40 c m$ . The focal length of the mirror is $40 c m$ . Find the position of image.

Object distance $u = - 40 c m$
Focal length $f = 40 c m$
Using mirror formula : $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
Or $\frac{1}{v} + \frac{1}{(- 40)} = \frac{1}{(40)}$
We get $v = 20 c m$

A point light source is kept in front of a convex mirror ata distance of 40cm. The focal length of the mirror is 40cm. Find the position of image.

Object distance u=−40 cmFocal length f=40 cmUsing mirror formula : 1v+1u=1fOr 1v+1(−40)=1(40)We get v=20 cm

A point light source is kept in front of a convex mirror ata distance of $40 c m$ . The focal length of the mirror is $40 c m$ . Find the position of image.

Object distance $u = - 40 c m$
Focal length $f = 40 c m$
Using mirror formula : $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
Or $\frac{1}{v} + \frac{1}{(- 40)} = \frac{1}{(40)}$
We get $v = 20 c m$