A pole 15 m long rests against a vertical wall an angle of displaystyle 30-circ- with the ground How high up the wall does the pole reach-7-5 m8 m5 m7 m

Question

Toppr Admin · Accepted Answer

The correct option is C 7-5 mAs shown in the fig- let AB be the length of the pole-sin30-x2218-x15Or-xA0-x-15sin30-x2218-152-7-5m

A pole $15$ m long rests against a vertical wall at an angle of $30^{\circ}$ with the ground How high up the wall does the pole reach?
$7.5$ m
$8$ m
$5$ m
$7$ m

The correct option is C $7.5$ m
As shown in the fig. let $A B$ be the length of the pole.

$sin 30^{\circ} = \frac{x}{15}$

Or

$x = 15 sin 30^{\circ} = \frac{15}{2} = 7.5$ m

A pole 15 m long rests against a vertical wall at an angle of 30∘ with the ground How high up the wall does the pole reach?7.5 m8 m5 m7 m

The correct option is C 7.5 mAs shown in the fig. let AB be the length of the pole.sin30∘=x15Or x=15sin30∘=152=7.5m

A pole $15$ m long rests against a vertical wall at an angle of $30^{\circ}$ with the ground How high up the wall does the pole reach?
$7.5$ m
$8$ m
$5$ m
$7$ m

The correct option is C $7.5$ m
As shown in the fig. let $A B$ be the length of the pole.

$sin 30^{\circ} = \frac{x}{15}$

Or

$x = 15 sin 30^{\circ} = \frac{15}{2} = 7.5$ m