A polyatomic gas left - gamma -dfrac-4-3- right - is compressed to dfrac-1-8- of its volume adiabatically- If its initial pressure is P- the new pressure will be8P16P6P2P

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Toppr Admin · Accepted Answer

In an adiabatic process we have P-xD7-V-x3B3- constant -orPf-P-V1V2-43Therefore if V become 1-8 - Substituting values in the equation will give final P to be 16P-

A polyatomic gas $(γ = \frac{4}{3})$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is P, the new pressure will be
$8 P$
$16 P$
$6 P$
$2 P$

In an adiabatic process we have $P \times V^{γ}$ constant .
or
$P_{f} = P (\frac{V_{1}}{V_{2}})^{\frac{4}{3}}$
Therefore if V become 1/8 . Substituting values in the equation will give final P to be 16P.

A polyatomic gas (γ=43) is compressed to 18 of its volume adiabatically. If its initial pressure is P, the new pressure will be8P16P6P2P

In an adiabatic process we have P×Vγ constant .orPf=P(V1V2)43Therefore if V become 1/8 . Substituting values in the equation will give final P to be 16P.

A polyatomic gas $(γ = \frac{4}{3})$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is P, the new pressure will be
$8 P$
$16 P$
$6 P$
$2 P$

In an adiabatic process we have $P \times V^{γ}$ constant .
or
$P_{f} = P (\frac{V_{1}}{V_{2}})^{\frac{4}{3}}$
Therefore if V become 1/8 . Substituting values in the equation will give final P to be 16P.