A polygon has 44 diagonals- Find the number of its sides-

Question

Toppr Admin · Accepted Answer

Let there be n sides of the polygon- We know that number of diagonals of n sided polygon is -dfrac-n-n-3-2-Therefore-dfrac-n-n-3-2-44-n-2-3n-88-0-n-11-n-8-0-n-11-160- as -n- is positiveHence- there are 11 sides of the polygon-

A polygon has $$44$$ diagonals. Find the number of its sides.

Let there be n sides of the polygon. We know that number of diagonals of n sided polygon is $$\dfrac{n(n-3)}{2}$$.

Therefore,
$$\dfrac{n(n-3)}{2}=44$$

$$n^2-3n-88=0$$

$$(n-11)(n+8)=0$$

$$n=11$$ as $$n$$ is positive

Hence, there are 11 sides of the polygon.

A polygon has $$44$$ diagonals. Find the number of its sides.

Let there be n sides of the polygon. We know that number of diagonals of n sided polygon is $$\dfrac{n(n-3)}{2}$$.Therefore,$$\dfrac{n(n-3)}{2}=44$$$$n^2-3n-88=0$$$$(n-11)(n+8)=0$$$$n=11$$ as $$n$$ is positiveHence, there are 11 sides of the polygon.

Let there be n sides of the polygon. We know that number of diagonals of n sided polygon is $$\dfrac{n(n-3)}{2}$$.

Therefore,
$$\dfrac{n(n-3)}{2}=44$$

$$n^2-3n-88=0$$

$$(n-11)(n+8)=0$$

$$n=11$$ as $$n$$ is positive

Hence, there are 11 sides of the polygon.