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# A position dependent force F=7−2x+3x2 newton (where x is in meter) on a small body of mass 2 Kg & displace it from x=0 to x=5 m. Calculate the work done.

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#### Step 1: Work doneWork done for small displacement can be defined as: dW=Fdx ....(1)Step 2: Integrate the equationTotal work done can be calculated by integrating the equation (1) with limits x=0 to x=5m ∫dW=5∫0Fdx ∫dW=5∫0(7−2x+3x2)dx ⇒W=[7x−2x22+3x33]50 ⇒W=35−25+125=135 JHence, the work done is 135 J

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