A Positive charge particle with velocity →v=x^i+y^j moves in a magnetic field →B=y^i+x^j. The magnitude of magnetic force acting on the particles is F. Which one of the following statements are correct :
no force will act on particle of x = y
F∝(x2−y2) if x > y
the force will act along positive Z-axis if x > y
the force will act along positive Z-axis if y > x
A
F∝(x2−y2) if x > y
B
the force will act along positive Z-axis if y > x
C
no force will act on particle of x = y
D
the force will act along positive Z-axis if x > y
Open in App
Solution
Verified by Toppr
The magnetic force on a particle moving with velocity 'v' in a given magnetic field is given by →F=→v×→B →F=(xi+yj)×(yi+xj) →F=x2k+y2(−k) →F=x2k−y2k If x=y,F=(x2−y2)k=0 F>0 if x>y. So the force acts in positive z- direction if x > y
Was this answer helpful?
0
Similar Questions
Q1
A Positive charge particle with velocity →v=x^i+y^j moves in a magnetic field →B=y^i+x^j. The magnitude of magnetic force acting on the particles is F. Which one of the following statements are correct :
View Solution
Q2
A charged particle with velocity →v=x^i+y^j moves in a magnetic field →B=y^i+x^j. The magnitude of magnetic force acting on the particles F. Among the following the correct statement(s) is/are :
View Solution
Q3
A charged particle with velocity →v=x^i+y^j moves in a magnetic field →B=y^i+x^j. The force acting on the particle has magnitude F. Which one of the following statements is/are correct?
View Solution
Q4
Assertion :A charged particle moves along positive y-axis with constant velocity in uniform electric and magnetic fields.If magnetic field is acting along positive x-axis,then electric field should act along positive z-axis. Reason: To keep the charged particle undeviated the relation →E=→B×→v must hold good.
View Solution
Q5
If a particle of charge q is moving with velocity v along the z - axis and the magnetic field B is acting along x - axis, use the expression →F=q(→v×→B) to find the direction of the force F acting on it.