A Positive charge particle with velocity v=xi^+yj^ moves in a magnetic field B=yi^+xj^. The magnitude of magnetic force acting on the particles is F. Which one of the following statements are correct :
This question has multiple correct options
A
no force will act on particle of x = y
B
F∝(x2−y2) if x > y
C
the force will act along positive Z-axis if x > y
D
the force will act along positive Z-axis if y > x
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Updated on : 2022-09-05
Solution
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Correct options are A) , B) and C)
The magnetic force on a particle moving with velocity 'v' in a given magnetic field is given by F=v×B F=(xi+yj)×(yi+xj) F=x2k+y2(−k) F=x2k−y2k If x=y,F=(x2−y2)k=0 F>0 if x>y. So the force acts in positive z- direction if x > y
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