A potential difference of Delta Vexists between two plates of a parallel-plate capacitor with capacitance C - A dielectric with a dielectric constant of k is then placed between the plates of the capacitor- What is the energy stored in the capacitor-dfrac-1-2- -C- k- -Delta V-2dfrac-1-2- -k-C- -Delta V-2dfrac-1-2- kC -Delta V-2dfrac-1-2- kC Delta Vdfrac-1-2- -C- k- Delta V

Question

Toppr Admin · Accepted Answer

When the dielectric is inserted in -xA0-between plates- the capacitance of the capacitor becomes C-x2032-KCThus- now the energy stored- U-x2032-12C-x2032-V2-12-KC-x394-V-2

A potential difference of ΔVexists between two plates of a parallel-plate capacitor with capacitance C . A dielectric with a dielectric constant of k is then placed between the plates of the capacitor. What is the energy stored in the capacitor?12(C/k)(ΔV)212(k/C)(ΔV)212kC(ΔV)212kCΔV12(C/k)ΔV

When the dielectric is inserted in between plates, the capacitance of the capacitor becomes C′=KCThus, now the energy stored, U′=12C′V2=12(KC)(ΔV)2

When the dielectric is inserted in between plates, the capacitance of the capacitor becomes $C^{'} = K C$
Thus, now the energy stored, $U^{'} = \frac{1}{2} C^{'} V^{2} = \frac{1}{2} (K C) (Δ V)^{2}$