A prism having an apex angle of 40 and refractive index of 1.50 is located in front of a vertical plane mirror as shown.A horizontal ray of light is incident on the prism. The total angle through which the ray is deviated is:
40 clockwise
20 clockwise
1780 clockwise
80 clockwise
A
20 clockwise
B
1780 clockwise
C
80 clockwise
D
40 clockwise
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Solution
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We have the deviation of prism, δ1=A(μ−1)=4o(1.5−1) ⟹δ1=2o For a plane mirror, i=2o δ2=180−2(2o)=176o ⟹δ=δ1+δ2=176o+2o=178o
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