A proton, a deuteron and an α-particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their kinetic energies?
1:2:1
2:1:1
2:2:1
1:1:2
A
2:2:1
B
1:2:1
C
1:1:2
D
2:1:1
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Solution
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Kinetic energy gained by charged particle of charge q when accelerated under a potential difference V will be KE=qV For a given V,KE∝q For proton, deuteron and α-particle the ratio of charges is 1:1:2
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