A proton and a neutron combine to give a deuterium nucleus.If $m_{o}$ and $m_{p}$ be the mass of neutron and proton respectively, then mass of deuterium nucleus is
equal to $m_{o}$ + $m_{p}$
more than $m_{o}$ + $m_{p}$
less than $m_{o}$ + $m_{p}$
can be less than or more than $m_{o}$ + $m_{p}$

Question

A proton and a neutron combine to give a deuterium nucleus.If $m_{o}$ and $m_{p}$ be the mass of neutron and proton respectively, then mass of deuterium nucleus is
equal to $m_{o}$ + $m_{p}$
more than $m_{o}$ + $m_{p}$
less than $m_{o}$ + $m_{p}$
can be less than or more than $m_{o}$ + $m_{p}$

Toppr Admin · Accepted Answer

The energy released during this during this in form of gamma photon comes from mass defect- -i-e- E-mc2- where m is the mass defect-xA0-The mass of the deuterium nucleus -2-01355 u- is less than the sum of the masses of the proton -1-00728 u- and the neutron -1-00866 u- which is 2-01594 u-

A proton and a neutron combine to give a deuterium nucleus.If mo and mp be the mass of neutron and proton respectively, then mass of deuterium nucleus isequal to mo+mpmore than mo+mpless than mo+mpcan be less than or more than mo+mp

The energy released during this during this in form of gamma photon comes from mass defect. (i.e., E=mc2, where m is the mass defect). The mass of the deuterium nucleus (2.01355 u) is less than the sum of the masses of the proton (1.00728 u) and the neutron (1.00866 u), which is 2.01594 u.

A proton and a neutron combine to give a deuterium nucleus.If $m_{o}$ and $m_{p}$ be the mass of neutron and proton respectively, then mass of deuterium nucleus is
equal to $m_{o}$ + $m_{p}$
more than $m_{o}$ + $m_{p}$
less than $m_{o}$ + $m_{p}$
can be less than or more than $m_{o}$ + $m_{p}$