A proton and an alpha-particle enter a uniform magnetic field right angles to it with same velocity- The time period of alpha-particle as compared to that of proton- will befour timestwo timesone-fourthhalf

Question

Toppr Admin · Accepted Answer

Time Period T-2-x3C0-mqB-x2234-TalphaTproton-malphamproton-xD7-qprotonqalpha-41-xD7-12-2

A proton and an $α -$ particle enter a uniform magnetic field at right angles to it with same velocity. The time period of $α -$ particle as compared to that of proton, will be
four times
two times
one-fourth
half

Time Period $T = \frac{2 π m}{q B}$
$∴ \frac{T_{a l p h a}}{T_{p r o t o n}} = \frac{m_{a l p h a}}{m_{p r o t o n}} \times \frac{q_{p r o t o n}}{q_{a l p h a}} = \frac{4}{1} \times \frac{1}{2} = 2$

A proton and an α−particle enter a uniform magnetic field at right angles to it with same velocity. The time period of α−particle as compared to that of proton, will befour timestwo timesone-fourthhalf

Time Period T=2πmqB∴TalphaTproton=malphamproton×qprotonqalpha=41×12=2

A proton and an $α -$ particle enter a uniform magnetic field at right angles to it with same velocity. The time period of $α -$ particle as compared to that of proton, will be
four times
two times
one-fourth
half

Time Period $T = \frac{2 π m}{q B}$
$∴ \frac{T_{a l p h a}}{T_{p r o t o n}} = \frac{m_{a l p h a}}{m_{p r o t o n}} \times \frac{q_{p r o t o n}}{q_{a l p h a}} = \frac{4}{1} \times \frac{1}{2} = 2$