A proton has kinetic energy $E = 100 k e V$ which is equal to that of a photon. The wavelength of photon is $λ_{2}$ and that of proton is $λ_{1}$ . The ratio of $λ_{1} / λ_{2}$ is proportional to

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Answer 1

For proton and photon wavelength is given as -
$λ_{p r o t o n} = \frac{h}{2 m E}, λ_{p h o t o n} = \frac{h c}{E}$ .

So, the answer is option (B).

Answer 2

For proton and photon wavelength is given as -

λ_{p r o t o n} = \frac{h}{2 m E}, λ_{p h o t o n} = \frac{h c}{E}

.

So, the answer is option (B).

A proton has kinetic energy $E = 100 k e V$ which is equal to that of a photon. The wavelength of photon is $λ_{2}$ and that of proton is $λ_{1}$ . The ratio of $λ_{1} / λ_{2}$ is proportional to

$E^{2}$

$E^{1 / 2}$

$E^{- 1}$

$E^{- 1 / 2}$

Solution

For proton and photon wavelength is given as -
$λ_{p r o t o n} = \frac{h}{2 m E}, λ_{p h o t o n} = \frac{h c}{E}$ .

So, the answer is option (B).

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The energy of photon of wavelength $λ$ is

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The energy of a photons is equal to the kinetic energy of a proton. If $λ_{1}$ is the de-Broglie wavelength of a proton, $λ_{2}$ the wavelength associated with the photon, and if the energy of the photon is E, then $(λ_{1} / λ_{2})$ is proportional to:

Complete and balance the following reactions (i) 92 $U^{235} +_{o} n^{1} \to \dots \dots . +_{52}$ Te $137 +_{40}$ Zr97
(ii) 34 Se $86 \to \dots \dots . + 2_{- 1} e^{o}$

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A proton has kinetic energy E=100keV which is equal to that of a photon. The wavelength of photon is λ2​ and that of proton is λ1​. The ratio of λ1​/λ2​ is proportional to

E2

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E−1

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For proton and photon wavelength is given as -λproton​=2mE​h​, λphoton​=Ehc​. So, the answer is option (B).

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The energy of photon of wavelength λ is

Two sources A and B have same power. The wavelength of radiation of A is λa​ and that of B is λb​. The number of photons emitted per second by A and B are na​ & nb​ respectively, then,

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The energy of a photons is equal to the kinetic energy of a proton. If λ1​ is the de-Broglie wavelength of a proton, λ2​ the wavelength associated with the photon, and if the energy of the photon is E, then (λ1​/λ2​) is proportional to:

Complete and balance the following reactions (i) 92 U235+o​n1→…….+52​ Te 137+40​ Zr97 (ii) 34 Se 86→…….+2−1​eo

More From Chapter

Dual Nature of Radiation and Matter

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A proton has kinetic energy $E = 100 k e V$ which is equal to that of a photon. The wavelength of photon is $λ_{2}$ and that of proton is $λ_{1}$ . The ratio of $λ_{1} / λ_{2}$ is proportional to

$E^{2}$

$E^{1 / 2}$

$E^{- 1}$

$E^{- 1 / 2}$

For proton and photon wavelength is given as -
$λ_{p r o t o n} = \frac{h}{2 m E}, λ_{p h o t o n} = \frac{h c}{E}$ .

So, the answer is option (B).

The energy of photon of wavelength $λ$ is

Two sources A and B have same power. The wavelength of radiation of A is $λ_{a}$ and that of B is $λ_{b}$ . The number of photons emitted per second by A and B are $n_{a}$ & $n_{b}$ respectively, then,

The energy of a photons is equal to the kinetic energy of a proton. If $λ_{1}$ is the de-Broglie wavelength of a proton, $λ_{2}$ the wavelength associated with the photon, and if the energy of the photon is E, then $(λ_{1} / λ_{2})$ is proportional to:

Complete and balance the following reactions (i) 92 $U^{235} +_{o} n^{1} \to \dots \dots . +_{52}$ Te $137 +_{40}$ Zr97
(ii) 34 Se $86 \to \dots \dots . + 2_{- 1} e^{o}$