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# A proton in a uniform electric field moves along a straight line with constant acceleration starting from rest. If it attains a velocity 4×103km/s at a distance of 2cm, the time required to reach the given velocity is :10−8s10−5s10−3s10−6s

A
105s
B
106s
C
108s
D
103s
Solution
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#### v2=u2+2asu=0,s=2×10−2mta=v22s=(4×103×103)22×2×10−2m/s2a=4×1014

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