A proton is fired from very far away towards a nucleus with charge Q = 120 e, where e is the electronic charge. It makes a closest approach of 10 fm to the nucleus. The de Broglie wavelength (in units of fm) of the proton at its start is :
(take the proton mass, mp=(5/3)×10−27kg and
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Correct option is A)
q2=e ( charge on proton)
is based on conservation of energy of proton.
we know, de’broglie wavelength,
A is correct.
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