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Standard XII
Physics
Question
A proton is moving with a velocity of
3
×
10
7
m
/
s
in the direction of a uniform magnetic field of
0.5
T
. The force acting on proton is
2
N
zero
4
N
6
N
A
2
N
B
4
N
C
6
N
D
zero
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Solution
Verified by Toppr
→
F
m
a
g
n
e
t
i
c
=
q
(
→
v
×
→
B
)
Since
→
v
∥
→
B
→
F
m
a
g
n
e
t
i
c
=
0
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