A proton is traveling due north- If a uniform magnetic field is applied vertically down then the particlea- deflected towards westb- revolves in anti clock wise directionc- acquires acceleration d- comes to resta- b- c are correctb- c- d are correctb- d are wronga- d are wrong

Question

Toppr Admin · Accepted Answer

-x2192-F-q-x2192-V-xD7-x2192-B-So- -x2192-V-xD7-x2192-B direction will be in west by right hand thumb rule- So- it will revolves in anti-clockwise direction and it acquires radial acceleration-

(a) towards south	(b) towards east
(c) downward	(d) upward

A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particle
a) deflected towards west
b) revolves in anti clock wise direction
c) acquires acceleration
d) comes to rest
a, b, c are correct
b, c, d are correct
b, d are wrong
a, d are wrong

$\to F = q (\to V \times \to B)$
So, $\to V \times \to B$ direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.

A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particlea) deflected towards westb) revolves in anti clock wise directionc) acquires acceleration d) comes to resta, b, c are correctb, c, d are correctb, d are wronga, d are wrong

→F=q(→V×→B)So, →V×→B direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.

A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particle
a) deflected towards west
b) revolves in anti clock wise direction
c) acquires acceleration
d) comes to rest
a, b, c are correct
b, c, d are correct
b, d are wrong
a, d are wrong

$\to F = q (\to V \times \to B)$
So, $\to V \times \to B$ direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.