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# A proton moving in a straight line enters a strong magnetic field along the field direction then its path and velocity will bepath is circular but speed constantpath is same but velocity increasespath is same and velocity remains constantpath is same and motion is retarded

A
path is same and velocity remains constant
B
path is circular but speed constant
C
path is same but velocity increases
D
path is same and motion is retarded
Solution
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#### F=q(→V×→B)=qVBsin0=qVBsin00(∵V and B has same direction)=0(∵sin00=0)So, there is no force, so, path is same and velocity is constant.

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