A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected if
E is parallel to V and perpendicular to B
E, V and B are mutually perpendicular and $V = E / B$
E is parallel to B and both are perpendicular to V
E is perpendicular to B

Question

A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected if
E is parallel to V and perpendicular to B
E, V and B are mutually perpendicular and $V = E / B$
E is parallel to B and both are perpendicular to V
E is perpendicular to B

Toppr Admin · Accepted Answer

Force due to magnetic field -Force due to electric fieldq-x2192-V-xD7-x2192-B-q-x2192-E-x21D2-x2192-V-xD7-x2192-B-x2192-ESo- E- V and B are mutually perpendicular and VB - E-xA0-xA0-xA0- -x2235-sin900-1-or V-EB

A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected ifE is parallel to V and perpendicular to BE, V and B are mutually perpendicular and V=E/BE is parallel to B and both are perpendicular to VE is perpendicular to B

Force due to magnetic field =Force due to electric fieldq(→V×→B)=q→E⇒→V×→B=→ESo, E, V and B are mutually perpendicular and VB = E (∵sin900=1)or V=EB

A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected if
E is parallel to V and perpendicular to B
E, V and B are mutually perpendicular and $V = E / B$
E is parallel to B and both are perpendicular to V
E is perpendicular to B

Force due to magnetic field $=$ Force due to electric field
$q (\to V \times \to B) = q \to E$
$\Rightarrow \to V \times \to B = \to E$
So, E, V and B are mutually perpendicular and VB = E $(∵ s i n 90^{0} = 1)$
or $V = \frac{E}{B}$