A proton of mass 1.67×10−27 kg and charge 1.68×10−19 C is projected with a speed of 2×106ms−1 at an angle of 60o to the X−axis. If a uniform magnetic field of 0.10 T is applied along Y−axis, the path of proton is :
A
a circle of radius 0.2 m and time period π×10−7s
B
a circle of radius 0.1 m and time period 2π×10−7s
C
a helix of radius 0.1 m and time period 2π×10−7s
D
a helix of radius 0.2 m and time period 4π×10−7s
Medium
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Updated on : 2022-09-05
Solution
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Correct option is C)
vx=vcosθ vy=vsinθ Since vy=0, this component will be responsible for motion along the direction B( i.e y−axis). The path will be helical and pitch will be constant. Radius r of the circle perpendicular to the magnetic field B