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Correct option is B)

$t=100×10_{−9}sec,P=30×10_{−3}$Watt,

$C=3×10_{8}m/s$

Incident energy $=Pt$

By debroglie wavelength, $λ=h/p$

and Energy of photon is $E=hc/λ$

From above two equations, $E=pc$

Momentum $p=CPt =3×10_{8}30×10_{−3}×100×10_{−9} =1.0×10_{−17}$ kg ms$_{−1}$

So, the answer is option (B).

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