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Updated on : 2022-09-05

Solution

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Correct option is D)

$λ_{1}=t_{1}1 $

$λ_{2}=t_{2}1 $

First order decay:

$dtdN =−(λ_{1}N+λ_{2}N)$

$dtdN =−(λ_{1}+λ_{2})$

$dtdN =−(t_{1}1 +t_{2}1 )N$

$dtdN =−(t_{1}t_{2}t_{1}+t_{2} )N$

$dtdN =−λ_{eff}N$

$t_{eq}=λ_{eff}1 $

$dtdN =−(λ_{1}N+λ_{2}N)$

$dtdN =−(λ_{1}+λ_{2})$

$dtdN =−(t_{1}1 +t_{2}1 )N$

$dtdN =−(t_{1}t_{2}t_{1}+t_{2} )N$

$dtdN =−λ_{eff}N$

$t_{eq}=λ_{eff}1 $

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