A radioactive sample has 5000 disintegration per minute initially and 1250 disintegration per minute after 5 seconds- Then the decay constant is0-2 20-8 20-1 20-4 ln2

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Toppr Admin · Accepted Answer

Using formulae-xA0-  N-Noe-x2212-x3BB-t

A radioactive sample has $5000$ disintegration per minute initially and $1250$ disintegration per minute after $5$ seconds. Then the decay constant is
$0.2 l n 2$
$0.8 l n 2$
$0.1 l n 2$
$0.4 l n 2$

Using formulae, $N = N_{o} e^{- λ t}$

A radioactive sample has 5000 disintegration per minute initially and 1250 disintegration per minute after 5 seconds. Then the decay constant is0.2ln20.8ln20.1ln20.4ln2

Using formulae, N=Noe−λt

A radioactive sample has $5000$ disintegration per minute initially and $1250$ disintegration per minute after $5$ seconds. Then the decay constant is
$0.2 l n 2$
$0.8 l n 2$
$0.1 l n 2$
$0.4 l n 2$

Using formulae, $N = N_{o} e^{- λ t}$