A radioactive substance after 48 days remains 25% of initial. Find disintegration constant.
$2.89 \times 10^{- 2} T^{- 1}$
$3.89 \times 10^{- 3} T^{- 1}$
$4.89 \times 10^{- 2} T^{- 1}$
none of these

Question

A radioactive substance after 48 days remains 25- of initial- Find disintegration constant-2-89 times 10-2- T-1-3-89 times 10-3- T-1-4-89 times 10-2- T-1-none of these

Toppr Admin · Accepted Answer

A radioactive substance after 48 days remains 25% of initial. Find disintegration constant.2.89×10−2T−13.89×10−3T−14.89×10−2T−1none of these

A radioactive substance after 48 days remains 25% of initial. Find disintegration constant.
$2.89 \times 10^{- 2} T^{- 1}$
$3.89 \times 10^{- 3} T^{- 1}$
$4.89 \times 10^{- 2} T^{- 1}$
none of these