μ=sin530sinr1 at first refraction on surface AB
μ=sin370sinr2 at surface AC
when ∠i decreases it means angle ∠r1 also decreases because refractive index is constant.
from the following reason we can conclude that
∠r1+∠r2=1800−A
when ∠r1 decreases then angle ∠r2 must increase.
therefore if ∠r2 increases then ∠e also increases.
In short we can say that if ∠i slightly decreases then ∠e slightly increases and vice versa
By solving equation 1 and 2 we get,
if angle of incidence become 50 degree then angle of emergence become 38 degree.
Option D is correct.