Question

# A ray is incident at an angle of incidence on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of the prism is μ, the angle of incidence i is nearly equal to :

A
A/μ
B
A/2μ
C
μ/A
D
μA
Solution
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#### Given data: The angle of incidence =iThe angle of the prism =AThe angle of emergence =ethe refractive index of the material of the prism is μ.For a small angle prism, angle of deviation, δ=(μ−1)A .......(i)Since, the ray emerges normally, ∴e=0By the relation,A+δ=i+eWe have, i=A+δor δ=(i−A) .........(ii)From Eqs. (i) and (ii)(i−A)=(μ−1)A⇒i=μA.

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