Question

Open in App

Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is B)

1 sin $90_{∘}$ $=μ_{1}$ sin $r_{1}⇒$ sin $r_{1}=2 1 ⇒r_{1}=45_{∘}$

We have the incident angle for the second interface given using the relation sin$i_{2}$=cos$r_{1}$

Thus we get

$μ_{1}$ cos $r_{1}$= $μ_{2}$ sin $r_{2}⇒$ sin $r_{2}$ = $μ_{2}1 $(cos$r_{2}$=$2 1 $)

$μ_{2}$ cos $r_{2}=μ_{3}$ sin $r_{3}$ $⇒$ sin $r_{3}$ $=3 μ_{2}1−sin_{2}r_{2} $

$μ_{3}$ cos $r_{3}=1$ = $3 μ_{2}−1 $

sin $_{2}r_{3}$ + cos $_{2}r_{3}=1$

$⇒3μ_{2}−1 +31 =1⇒μ_{2}_{2}=3⇒μ_{2}=3 $

Thus we get $x=3.$

Video Explanation

Solve any question of Ray Optics and Optical Instrument with:-

Was this answer helpful?

0

0