A ray of light falls on a transparent sphere with centre at $C$ is shown in Fig.
The ray emerges from the sphere parallel to line $A B$ . The refractive index of the sphere is

Question

A ray of light falls on a transparent sphere with centre C is shown in Fig-The ray emerges from the sphere parallel to line AB- The refractive index of the sphere issqrt -3-3-21-2sqrt -2-

Toppr Admin · Accepted Answer

Deviation by a sphere is 2-i-x2212-Here- deviation -x3B4-60-x2218-2-i-x2212-r-or i-x2212-r-30-x2218-x2234-r-i-x2212-30-x2218-60-x2218-x2212-30-x2218-30-x2218-x2234-x3BC-sinisinr-sin60-x2218-sin30-x2218-x221A-3-

A ray of light falls on a transparent sphere with centre at $C$ is shown in Fig.
The ray emerges from the sphere parallel to line $A B$ . The refractive index of the sphere is

$\sqrt{3}$
$3 / 2$
$1 / 2$
$\sqrt{2}$

Deviation by a sphere is $2 (i -)$
Here, deviation $δ = 60^{\circ} = 2 (i - r)$
or $i - r = 30^{\circ}$
$∴ r = i - 30^{\circ} = 60^{\circ} - 30^{\circ} = 30^{\circ}$
$∴ μ = \frac{sin i}{sin r} = \frac{sin 60^{\circ}}{sin 30^{\circ}} = \sqrt{3}$ .

A ray of light falls on a transparent sphere with centre at C is shown in Fig.The ray emerges from the sphere parallel to line AB. The refractive index of the sphere is√33/21/2√2

Deviation by a sphere is 2(i−)Here, deviation δ=60∘=2(i−r)or i−r=30∘∴r=i−30∘=60∘−30∘=30∘∴μ=sinisinr=sin60∘sin30∘=√3.

A ray of light falls on a transparent sphere with centre at $C$ is shown in Fig.
The ray emerges from the sphere parallel to line $A B$ . The refractive index of the sphere is

$\sqrt{3}$
$3 / 2$
$1 / 2$
$\sqrt{2}$

Deviation by a sphere is $2 (i -)$
Here, deviation $δ = 60^{\circ} = 2 (i - r)$
or $i - r = 30^{\circ}$
$∴ r = i - 30^{\circ} = 60^{\circ} - 30^{\circ} = 30^{\circ}$
$∴ μ = \frac{sin i}{sin r} = \frac{sin 60^{\circ}}{sin 30^{\circ}} = \sqrt{3}$ .