A ray of light incident an angle theta on a refracting face of prism emerges from the other face normally- If the angle of the prism is 5 and the prism is made of material of refractive index 1-5- the angle of incidence is7-5-circ-5-circ-15-circ-2-5-circ-

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We have deviation- -x3B4-M-x2212-1-A-x3B4-1-5-x2212-1-5-x2218-2-5-x2218-The angle of the prism is 50-xB0-The ray emerges from refracting face of a prism normally-Then- i2-r2-0As- A-r1-r2-0r1-Ar1-50-xB0-But i1-x3BC-r1-32-xD7-5-7-5-xB0-

A ray of light incident at an angle θ on a refracting face of prism emerges from the other face normally. If the angle of the prism is 5 and the prism is made of material of refractive index 1.5, the angle of incidence is7.5∘.5∘.15∘.2.5∘.

We have deviation, δ=(M−1)Aδ=(1.5−1)5∘=2.5∘The angle of the prism is 50°.The ray emerges from refracting face of a prism normally.Then, i2=r2=0As, A=r1+r2=0r1=Ar1=50°But i1=μr1=32×5=7.5°

A ray of light incident at an angle $θ$ on a refracting face of prism emerges from the other face normally. If the angle of the prism is $5$ and the prism is made of material of refractive index $1.5$ , the angle of incidence is
${7.5}^{\circ}$ .
$5^{\circ}$ .
$15^{\circ}$ .
${2.5}^{\circ}$ .